Final answer:
To find the equation of a line parallel to x + 5= 0 that passes through the point ( -6, -10), we need to determine the slope of the given line. The slope is -1. Using the point-slope form of a linear equation, y - y1 = m(x - x1), we can substitute the values and simplify the equation to get y = -x - 16.
Step-by-step explanation:
To find the equation of a line parallel to x + 5 = 0 that passes through the point (-6, -10), we need to determine the slope of the given line. The equation x + 5 = 0 is in the form x + b = 0, where the coefficient of x represents the slope. In this case, the slope is -1. Since the line we want is parallel to this one, it will have the same slope of -1.
Now, we can use the point-slope form of a linear equation to find the equation of the parallel line. The point-slope form is y - y1 = m(x - x1), where (x1, y1) is a point on the line and m is the slope.
Substituting the provided values into the equation, we get y + 10 = -1(x + 6). Now, we can simplify this equation to slope-intercept form, y = -x - 16.