Final answer:
The pressure exerted by water on the base of a beaker filled to one-third of its 12m height with a 10 cm square base is 39200 Pascals.
Step-by-step explanation:
To calculate the pressure exerted by water on the base of the beaker, we need to use the formula for pressure (P) which is the force (F) exerted on an area (A). The force due to the water is the weight of the water, which is the volume of the water times the density (ρ) times gravitational acceleration (g). For the beaker one third filled, the height (h) is 12 m / 3 = 4 m. The base area (A) of the beaker is 10 cm x 10 cm = 0.1 m x 0.1 m = 0.01 m². Assuming the density of water is 1000 kg/m³ and g is 9.8 m/s², the pressure can be calculated.The pressure exerted by water on the base of the beaker can be calculated using the formula:Pressure = Force/Area
First, we need to calculate the force exerted by the water. To do this, we need to find the weight of the water. Since the beaker is filled one-third, the volume of water is (1/3) * (12m * 10cm * 10cm). We convert the dimensions to meters and multiply by the density of water to get the mass. The weight of the water is then the mass multiplied by the acceleration due to gravityNext, we calculate the area of the base of the beaker by multiplying the length and width. Finally, we divide the force by the area to get the pressure.Therefore, the pressure exerted by water on the base of the beaker, when one-third of it is filled, is (calculated value) units.The pressure exerted by the water is 39200 Pa (Pascals).We start by finding the volume of water in the one-third filled beaker, V = A * h, which is 0.01 m² * 4 m = 0.04 m³. Then we find the weight of the water, F = m * g = ρ * V * g = 1000 kg/m³ * 0.04 m³ * 9.8 m/s². Which gives us the force F = 392 N. The pressure is then P = F / A = 392 N / 0.01 m² = 39200 Pa.