Final answer:
The frequency of a tuning fork that completes one oscillation in 2.50 × 10⁻³ seconds is found using the formula f = 1/T, resulting in a frequency of 400 Hz.
Step-by-step explanation:
To find the frequency of a tuning fork that completes one oscillation in a given period of time, you can use the formula f = 1/T, where f is frequency and T is the period of oscillation. Given that one oscillation takes 2.50 × 10⁻³ seconds, we calculate the frequency as follows:
- Frequency (f) = 1/Period (T)
- Frequency (f) = 1/(2.50 × 10⁻³ s)
- Frequency (f) = 1/0.0025 s
- Frequency (f) = 400 Hz
Therefore, the frequency of the tuning fork is 400 hertz (Hz).