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If you burn 23.2 g of hydrogen and produce 207 g of water, how much oxygen reacted?

a. 183.8 g
b. 184.8 g
c. 206.8 g
d. 230 g

User Tura
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1 Answer

6 votes

Final answer:

By subtracting the mass of hydrogen from the mass of water produced, we find that 183.8 g of oxygen reacted with the hydrogen, making answer A the correct choice.

Step-by-step explanation:

When 23.2 g of hydrogen is burned to produce 207 g of water, we want to determine the mass of oxygen that reacted. From the given chemical equation 2H₂ + O₂ → 2H₂O, it is understood that 2 moles of hydrogen react with 1 mole of oxygen to form 2 moles of water. By using the molar masses of hydrogen (H₂ = 2.02 g/mol) and oxygen (O₂ = 32.0 g/mol), we can calculate the mass of oxygen that reacted.



To find the amount of oxygen, we subtract the mass of hydrogen used from the mass of water produced: 207 g (mass of H₂O) - 23.2 g (mass of H₂) gives us the mass of oxygen that reacted with hydrogen. This results in 183.8 g of O₂, which means Answer A is the correct choice.

User Whalemare
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