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Find the work done by the gas with an initial volume of 3 cubic feet and a pressure of 1000 pounds per square foot expands to the volume of 4 cubic feet (Assume that the pressure is inversely proportional to the volume).

(a) 284.68

(b) 285.68

(c) 286.68

(d) 287.68

1 Answer

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The work done by the gas is: (d) 287.68

The work done by the gas in an isobaric process (constant pressure) when the pressure is inversely proportional to the volume can be calculated using the formula:

W = P × ΔV × ln(Vf/Vi)

where:

W is the work done,

P is the pressure,

ΔV is the change in volume, and

ln⁡ is the natural logarithm.

Given an initial volume (Vi) of 3 cubic feet, a final volume (Vf) of 4 cubic feet, and an initial pressure of 1000 pounds per square foot, we can substitute these values into the formula to find the work done.

W = 1000 × (4−3) × ln(4/3)

W = 1000 × 1 × 0.28768

W = 1000 × 0.28768

W = 287.68

Therefore, the work done by the gas is 287.68 pounds per square foot. Hence, the correct answer is (d) 287.68.

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