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A line that includes the point (0,0) has the slope of 1/15. What is it’s equation in slop-intercept form?

User Seanjacob
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Answer:

y = (1/15)x (+ 0) [The y-intercept is 0]: y = (1/15)x

Explanation:

The standard slope/intercept form of a linear equation is y = mx + b, where m is the slope and b is the y-intercept (the value of y when x=0).

We are given a slope of (1/15) so we can write:

y = (1/15)x + b

The given point (0,0) just so happens to have the information for b, the y-intercept. b id the value of y when x=0. Point (0,0) tells us that the value of y when x=0 is 0 (aor at least will be when we develop the equation. So b = 0, and we progress to:

y= (1/15)x + 0

This is the equation in slope-intercept form.

A line that includes the point (0,0) has the slope of 1/15. What is it’s equation-example-1
User Peter Pointer
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