Final answer:
The concentration of Cl-(aq) in the resulting solution is 20.0 M.
Step-by-step explanation:
To determine the concentration of Cl-(aq) in the resulting solution, we need to consider the dilution that occurs when the 100.0 mL of 50.0 M SrCl2(aq) is added to 400.0 mL of distilled water.
The number of moles of SrCl2 in the 100.0 mL solution can be calculated as the product of its molarity and volume, which is (50.0 mol/L)(0.100 L) = 5.00 mol.
Since SrCl2 dissociates into one Sr2+ ion and two Cl- ions, there are 10.0 mol of Cl- ions in 5.00 mol of SrCl2.
When this solution is diluted to a final volume of 500.0 mL (100.0 mL SrCl2 + 400.0 mL water), the concentration of Cl-(aq) can be calculated as (10.0 mol)/(0.500 L) = 20.0 M.