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A balloon with 100.0 L of helium gas at 100.0 kPa and 25.00 °C rises to an altitude where the pressure is 75.0 kPa and the temperature is 0.00 °C. What is the new volume of the balloon?

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Final answer:

The new volume of the balloon is 444.44 L.

Step-by-step explanation:

To find the new volume of the balloon, we can use the combined gas law equation:

P1V1/T1 = P2V2/T2

Given:

  • P1 = 100.0 kPa
  • V1 = 100.0 L
  • T1 = 25.00 °C = 298.15 K
  • P2 = 75.0 kPa
  • T2 = 0.00 °C = 273.15 K

Plugging in the values into the equation:

(100.0 kPa)(100.0 L) / (298.15 K) = (75.0 kPa)(V2) / (273.15 K)

Solving for V2:

V2 = (100.0 L)(298.15 K) / (75.0 kPa)(273.15 K) = 444.44 L

Therefore, the new volume of the balloon is 444.44 L.

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