Question

Help please.
A student uses this apparatus to beat crystals or hydrated zinc

Answer 1

The maximum volume of pure water produced is approximately 12.8cm³.

To calculate the maximum volume of pure water produced during the decomposition of hydrated zinc sulfate, we need to find the mass of water released. The mass of water can be determined by the difference in mass before and after the reaction.

1. **Calculate the mass of water released:**

`\[ \text{Mass of water} = \text{Mass of boiling tube + ZnSO}_4\cdot7\text{H}_2\text{O} - \text{Mass of boiling tube} \]`

`\[ \text{Mass of water} = 54.46 \, \text{g} - 41.64 \, \text{g} = 12.82 \, \text{g} \]`

2. **Convert the mass of water to volume using the given conversion factor:**

`\[ \text{Volume of water} = \frac{\text{Mass of water}}{\text{Density of water}} \]`

Since 1.00 cm³ of pure water has a mass of 1.00g, the volume of water produced is 12.82 cm³.

In summary:

The maximum volume of pure water that could be produced during the decomposition of hydrated zinc sulfate is 12.8cm³ when rounded to one decimal place.

In conclusion, the student can expect to collect approximately 12.8 cm³ of pure water based on the mass measurements before and after the decomposition reaction.