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What is the result of performing an inorder traversal on the binary search tree after inserting the keys 8, 4, 12, 2, 6, 10, 14, 1, 3, 5, 7, 9, 11, 13, 15 in that order?

A) 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15
B) 15, 14, 13, 12, 11, 10, 9, 8, 7, 6, 5, 4, 3, 2, 1
C) 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14
D) 15, 13, 11, 9, 7, 5, 3, 1, 2, 4, 6, 8, 10, 12, 14

User Kiminoa
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Final answer:

The result of performing an inorder traversal on the binary search tree after inserting the keys 8, 4, 12, 2, 6, 10, 14, 1, 3, 5, 7, 9, 11, 13, 15 in that order is option A) 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15.

Step-by-step explanation:

The result of performing an inorder traversal on the binary search tree after inserting the keys 8, 4, 12, 2, 6, 10, 14, 1, 3, 5, 7, 9, 11, 13, 15 in that order is option A) 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15.

The inorder traversal visits the left subtree first, then the root, and finally the right subtree for each node.

  1. First, we insert 8 as the root.
  2. Next, we insert 4 as the left child of 8.
  3. Then, we insert 12 as the right child of 8.
  4. Continuing this way, the keys are inserted in the binary search tree.
  5. Performing an inorder traversal on this tree yields the desired result: 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15.
User Eratosthenes
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