Final answer:
The gas with the highest partial pressure is oxygen (O₂), and the gas with the lowest partial pressure is carbon dioxide (CO₂). The partial pressure of the orange gas can be calculated by multiplying its percentage content in the mixture by the total pressure. The partial pressure of oxygen at an altitude of 18,000 ft can be determined by multiplying its mole percentage in the atmosphere by the external air pressure.
Step-by-step explanation:
In the given mixture of four gases, the gas with the highest partial pressure is oxygen (O₂) because it constitutes 20.9% of atmospheric gas. The gas with the lowest partial pressure is carbon dioxide (CO₂) because it is found in relatively small amounts, only 0.04% of atmospheric gas.
The partial pressure of the orange gas can be calculated by multiplying its percentage content in the mixture by the total pressure. If the total pressure is 1.75 atm, and the orange gas constitutes x% of the mixture, the equation would be:
x% * 1.75 atm = partial pressure of the orange gas atm
Given the information provided, it is not possible to accurately determine the partial pressure of oxygen at an altitude of 18,000 ft. However, if oxygen constitutes 21 mol% of the atmosphere and the external air pressure is 0.49 atm, the partial pressure of oxygen can be calculated by:
0.21 * 0.49 atm = partial pressure of oxygen atm
To determine whether you will survive with a minimum required oxygen partial pressure of 0.15 atm, compare it to the calculated partial pressure of oxygen at 18,000 ft. If the calculated partial pressure of oxygen is higher than 0.15 atm, then you would have a sufficient oxygen supply to survive.