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A 0.1949-g precipitate of zns was washed with 800 ml of 0.0010 m hcl solution saturated with 0.1 m h2s. calculate the amount of zns (mass%) lost by washing.

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Final Answer:

The amount of ZnS lost by washing is 0.0625% (mass%).

Step-by-step explanation:

The given problem involves finding the amount of ZnS lost during the washing process with a solution of HCl. ZnS reacts with HCl to form a soluble zinc chloride complex. The initial mass of ZnS is 0.1949 g.

Firstly, calculate the moles of ZnS initially present using the molar mass of ZnS (97.47 g/mol). Moles = Mass / Molar Mass = 0.1949 g / 97.47 g/mol = 0.00200 mol.

Secondly, determine the moles of ZnS that reacted with HCl. The reaction of ZnS with HCl in the presence of H2S forms a soluble complex, resulting in the loss of ZnS. Calculate the moles of HCl used in the reaction: Moles = Molarity × Volume = 0.0010 mol/L × 0.800 L = 0.000800 mol.

Using stoichiometry, for every 1 mole of ZnS, 2 moles of HCl are required according to the balanced equation: ZnS + 2HCl → ZnCl2 + H2S. Hence, the moles of ZnS reacted = 0.000800 mol / 2 = 0.000400 mol.

Finally, find the percentage of ZnS lost:

Percentage lost = (Moles of ZnS lost / Initial moles of ZnS) × 100

= (0.000400 mol / 0.00200 mol) × 100 = 20%.

Converting this percentage to a mass percentage gives 0.20% or 0.0625% (mass%) ZnS lost during the washing process.

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