Final answer:
The initial acceleration of an alpha particle placed at a point in space where the electric field strength is 7.6x10^4 N/C is 3.68x10^7 m/s^2.
Step-by-step explanation:
The initial acceleration of an alpha particle placed at a point in space where the electric field strength is 7.6x104 N/C can be determined using the equation:
a = qE/m
Where:
- a is the acceleration
- q is the charge of the alpha particle
- E is the electric field strength
- m is the mass of the alpha particle
Substituting the given values:
- q = 3.2x10-19 C
- E = 7.6x104 N/C
- m = 6.64x10-27 kg
We can calculate the initial acceleration:
a = (3.2x10-19 C) x (7.6x104 N/C) / (6.64x10-27 kg) = 3.68x107 m/s2
Therefore, the initial acceleration of the alpha particle is 3.68x107 m/s2.