Question

the molar ratio of salt to acid needed to prepare a sodium acetate-acetic acid buffer solution is 1:1. assuming that the total buffer concentration is 0.1 mol/l, how many grams of sodium acetate (m.w. 82) should be used in preparing 2 liters of the solution?

Answer 1

To prepare a 2-liter solution with a total buffer concentration of 0.1 mol/l, you will need to use 16.4 grams of sodium acetate.

Step-by-step explanation:

To calculate the grams of sodium acetate needed to prepare a 2-liter solution with a total buffer concentration of 0.1 mol/l, we first need to calculate the number of moles of sodium acetate required. Since the molar ratio of salt to acid needed is 1:1, the number of moles of sodium acetate will be the same as the number of moles of acetic acid. Using the formula C = n/V, where C is the molar concentration, n is the number of moles, and V is the volume, we can calculate the number of moles of sodium acetate:

C = n/2

0.1 = n/2

n = 0.1 * 2 = 0.2 mol

Now we can calculate the grams of sodium acetate using the formula m = n * MW, where m is the mass, n is the number of moles, and MW is the molar mass:

m = 0.2 * 82 = 16.4 g