43.3k views
1 vote
An 80.0 gram sample of water at 10 degrees Celsius absorbs heat and reaches 50 degrees Celsius. What is the heat absorbed by the water?

A. 3200 J
B. 4000 J
C. 4800 J
D. 5600 J

User Zianwar
by
8.5k points

1 Answer

2 votes

Final answer:

To find the heat absorbed by water, the formula q = mcΔT is used with the values m = 80.0 g, c = 4.184 J/g°C, and ΔT = 40°C. The calculated heat absorbed is 13,392 J, which does not match any provided options.

Step-by-step explanation:

To calculate the heat absorbed by water, we use the formula q = mcΔT, where q is the heat absorbed in joules (J), m is the mass of the water in grams (g), c is the specific heat capacity of water (4.184 J/g°C), and ΔT is the change in temperature in Celsius (°C). In this case, the mass of water (m) is 80.0 g, the specific heat capacity (c) is 4.184 J/g°C, and the temperature change (ΔT) is 50°C - 10°C, which equals 40°C. Substituting these values into the formula, we get:q = (80.0 g) × (4.184 J/g°C) × (40°C) = 13392 J

Therefore, the answer closest to the heat absorbed by the water is 13,392 J, which is not one of the options provided in the question. Hence, there seems to be a mismatch between the options provided and the correct answer calculated.

User Sven Rojek
by
8.0k points