Question

suppose that months from now the population of a town will be growing at the rate of people per month. the initial population is 5000. what will be the population in years?

Answer 1

The student's question involves exponential growth of a town's population, with a doubling time of 10 years. Starting from 100 residents in 1900, the population would reach approximately 102,400 residents by the year 2000 using the exponential growth formula.

Step-by-step explanation:

The town in question demonstrates exponential growth. Given the initial population of 100 residents in 1900 and a doubling time of 10 years, we can calculate the population at future dates using the formula for exponential growth Population = Initial Population * 2^(Years/Double Time).

By applying this formula, we can validate the claim provided in the text that the population reaches approximately 100,000 residents by the year 2000. We do this by calculating the number of 10-year intervals from 1900 to 2000, which is 10 intervals (100 years / 10 years per interval), and then doubling the initial population of 100 residents 10 times (2^10 = 1024). Consequently, the population would be 100 * 1024, giving us 102,400 residents.