Question

consider the following voltaic cell: pb(s) | pb2 (1.0 m) || cu2 (1.0 m) | cu(s) based on the cell notation, what is the anode and what is the cathode?

Answer 1

In the given voltaic cell, Pb(s) serves as the anode where oxidation occurs, and Cu(s) is the cathode where reduction takes place.

Step-by-step explanation:

In a voltaic cell like the one described (Pb(s) | Pb2+ (1.0 M) || Cu2+ (1.0 M) | Cu(s)), we can identify the anode and cathode by considering the direction of the flow of electrons. In a galvanic or voltaic cell, the anode is where oxidation occurs, and the cathode is where reduction occurs. According to the cell notation provided, lead (Pb) is oxidized at the anode, and copper (Cu) is reduced at the cathode. Therefore, the anode of the cell is Pb(s) and the cathode is Cu(s).