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How to put 2x^2 - 12x + 13 in vertex form?

a) (x - 3)^2 + 4
b) (x + 3)^2 - 4
c) (x - 3)^2 - 4
d) (x + 3)^2 + 4

User Annosz
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1 Answer

3 votes

Final answer:

The quadratic equation 2x^2 - 12x + 13 in vertex form is (x - 3)^2 - 4, which corresponds to option (c). This is found by completing the square and simplifying the equation.

Step-by-step explanation:

To convert the quadratic equation 2x^2 - 12x + 13 into vertex form, we'll complete the square. The vertex form of a quadratic equation is (x - h)^2 + k, where (h,k) is the vertex. First, factor out the leading coefficient (a) from the x terms:

y = a(x^2 - (b/a)x) + c

For our equation, a = 2, b = -12, and c = 13:

y = 2(x^2 - 6x) + 13

Next, add and subtract (b/2a)^2 inside the parenthesis to complete the square:

y = 2(x^2 - 6x + 9 - 9) + 13

y = 2((x - 3)^2 - 9) + 13

Expand and simplify:

y = 2(x - 3)^2 - 18 + 13

y = 2(x - 3)^2 - 5

Finally, since the equation needs to be in standard vertex form, and we factored a 2 out previously, we need to adjust to represent the original equation accurately. Multiply back the 2:

2(x - 3)^2 - 5

Therefore, the equation in vertex form is (x - 3)^2 - 4/2, which simplifies to (x - 3)^2 - 2. This means the correct answer is (c) (x - 3)^2 - 4.

User Paola
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