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What is the electric field at a point 0.450 m to the left of a 5.77*10^-9 C charge? Include a + or - sign to indicate the direction of the field. (Unit = N/C)
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4 votes
4 votes
What is the electric field at a point

0.450 m to the left of a
5.77*10^-9 C charge?
Include a + or - sign to indicate the
direction of the field.

(Unit = N/C)

User ANemati
by
3.4k points

1 Answer

20 votes
20 votes

Answer:

E = 256.444 N/C

Step-by-step explanation:

E = kq/r²

E = 9*10^9 * 5.77*10^-9/(0.450)²

E = 51.93/0.2025

E = 256.444 N/C

User FeFiFoFu
by
3.1k points
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