89.9k views
4 votes
Find the local maximum and minimum of f(x,y)=y(e^x−1):

A. No local maximum or minimum
B. Local maximum at y=0 and no local minimum
C. Local minimum at y=0 and no local maximum
D. Local maximum at (0,0) and no local minimum

User Cherese
by
8.3k points

1 Answer

3 votes

Final answer:

The function f(x,y)=y(e^x-1) has no local maximum or minimum since y=0 is a critical line, but the function does not reach a maximum or minimum for any specific x value.

Step-by-step explanation:

To find the local maximum and minimum of the function f(x,y)=y(e^x-1), we need to calculate the partial derivatives and set them equal to zero to locate critical points. The function has no explicit dependence on y other than being multiplied directly, which means y=0 is always a critical line. By examining the behavior around y=0, we can determine the nature of this critical line. Since the exponentiated variable x only grows or decreases exponentially and never reaches a maximum or minimum except at negative infinity, no local maximum or minimum exists due to the multiplier y.

Therefore, the correct answer is A. No local maximum or minimum.

User Naresh S
by
9.1k points