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Find the Vertex Form f(x)=-1/2x²-2x+6

User Maynor
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Final answer:

To find the vertex form of the function f(x)=-1/2x²-2x+6, complete the square to transform the quadratic function into its vertex form, resulting in f(x) = -1/2(x + 2)² + 8.

Step-by-step explanation:

To find the vertex form of the given quadratic function f(x)=-1/2x²-2x+6, we need to complete the square.

Step 1: Factor out the coefficient of the x² term from the first two terms.

f(x) = -1/2(x² + 4x) + 6

Step 2: Find the number that completes the square for the expression in parentheses.

The number needed to complete the square is found using (b/2)², where b is the coefficient of x. In this case, b is 4, so (4/2)² = 4.
However, since we factored -1/2 out, we need to divide 4 by -1/2 to keep the equation balanced, which gives us -8.

Step 3: Add and subtract this number inside the parentheses and simplify.

f(x) = -1/2(x² + 4x + 4 - 4) + 6

= -1/2((x + 2)² - 4) + 6

Step 4: Distribute the -1/2 and simplify the entire equation.

f(x) = -1/2(x + 2)² + 2 + 6

= -1/2(x + 2)² + 8

The vertex form of the quadratic function is f(x) = -1/2(x + 2)² + 8.

User Giacomelli
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