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For the quadratic equation 11x² -6x -2=0, what are the solutions for x?

A) x=2,x=−1/11
B) x=1,x=−2/11
C) x=−2,x=1/11
D) x=−1,x=2/11

User Tmporaries
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1 Answer

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Final answer:

The solutions for x in the quadratic equation 11x² -6x -2=0 are approximately x = 0.0684 and x = -0.0185.

Step-by-step explanation:

The given quadratic equation is 11x² -6x -2=0. To find the solutions for x, we can use the quadratic formula.

The quadratic formula is: x = (-b ± √(b²-4ac)) / (2a)

Comparing the given equation to the standard form ax²+bx+c=0, we have a=11, b=-6, and c=-2.

Substituting these values into the quadratic formula, we get:
x = (-(-6) ± √((-6)²-4(11)(-2))) / (2(11))
Simplifying, we have:
x = (6 ± √(36+88)) / 22
x = (6 ± √(124)) / 22

So, the solutions for x are x = (6 + √(124)) / 22 and x = (6 - √(124)) / 22. To simplify these further, we can approximate the value of √124 as approximately 11.1355.

Therefore, the solutions for x are approximately x = 0.0684 and x = -0.0185.

User Irshad Ali
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