Final answer:
The value of cos x when sin x = 7/8 in quadrant I is sqrt(15)/8.
Step-by-step explanation:
To find the value of cos x when sin x = 7/8 in quadrant I, we can use the Pythagorean identity: sin^2(x) + cos^2(x) = 1. Substitute sin x = 7/8 into this equation: (7/8)^2 + cos^2(x) = 1. Solve for cos x: cos^2(x) = 1 - (7/8)^2 = 1 - 49/64 = 15/64. Taking the square root of both sides, we get: cos(x) = +sqrt(15)/8 or -sqrt(15)/8. Since x is in quadrant I, where cosine is positive, the correct answer is cos x = +sqrt(15)/8.