253,256 views
11 votes
11 votes
Can anyone help me pls I would appreciate it

Can anyone help me pls I would appreciate it-example-1
User Raja Simon
by
2.6k points

1 Answer

9 votes
9 votes

Answer:

t = b + n

Explanation:

for the 2 lines to be parallel then their slopes must be equal

calculate the slope m using the slope formula

m =
(y_(2)-y_(1) )/(x_(2)-x_(1) )

with (x₁, y₁ ) = (x₁, a + n ) and (x₂, y₂ ) = (x₂, t ) ← 2 points on line k

m =
(t-(a+n))/(x_(2)-x_(1) ) =
(t-a-n)/(x_(2)-x_(1) )

repeat with

(x₁, y₁ ) = (x₁, a ) and (x₂, y₂ ) = (x₂, b ) ← 2 points on line j

m =
(b-a)/(x_(2)-x_(1) )

equating the 2 slopes gives


(t-a-n)/(x_(2)-x_(1) ) =
(b-a)/(x_(2)-x_(1) )

since the denominators are the same on both sides, then equate the numerators

t - a - n = b - a ( add a to both sides )

t - n = b ( add n to both sides )

t = b + n

User Rimon
by
3.1k points
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.