Final answer:
The velocity of the body after 1 second from the start, when acted upon by a constant force of 20 N, is calculated to be 10 m/s using Newton's second law of motion.
Step-by-step explanation:
To determine the velocity of the body after 1 second from the start when a constant force acts upon it, we use the second law of motion which states that the force on an object is equal to the mass of the object multiplied by its acceleration (F = ma).
Given:
Force (F) = 20 N
Mass (m) = 2 kg
Time (t) = 1 second
First, we calculate the acceleration (a) using the force and mass:
a = F/m = 20 N / 2 kg = 10 m/s2
Now, since the body started from rest, its initial velocity (u) is 0 m/s. To find the final velocity (v) we use the equation:
v = u + at
v = 0 m/s + (10 m/s2)(1 s)
v = 10 m/s
The velocity of the body after 1 second from the start is 10 m/s.
To find the velocity of the body after 1 second, we can use the equation v = u + at, where v is the final velocity, u is the initial velocity (which is 0 in this case), a is the acceleration, and t is the time. Given that the force acting on the body is constant, we can use the equation F = ma, where F is the force, m is the mass, and a is the acceleration.
Rearranging the equation, we have a = F/m. Plugging in the values, we get a = 20 N / 2 kg = 10 m/s^2. Now, we can plug the values into the first equation to find the velocity: v = 0 + (10 m/s^2) * 1 s = 10 m/s.