Final answer:
The probability of getting a head and a tail alternately in three coin tosses is 1/4, as two sequences satisfy this condition, each with a probability of 1/8.
Step-by-step explanation:
The question is asking about the probability of getting a head and a tail alternately when a coin is tossed three times. To solve this, we must consider the different sequences in which heads (H) and tails (T) can occur.
For heads and tails to alternate, the only possible sequences are HTT and THT. The probability of HTT is (1/2) × (1/2) × (1/2) = 1/8, and the same calculation applies for THT.
Since these are the only two sequences that meet the criteria, we add their probabilities to find the total probability of this event: 1/8 + 1/8 = 1/4.
Therefore, the answer to the question is (b) 1/4.