Question

solvents used in this experiment were 5% sodium chloride (aq) and 5% isopropyl alcohol (aq). draw molecular diagrams of how sodium chloride and isopropyl alcohol would interact in water. identify the type of intermolecular attraction within each diagram..

Answer 1

Sodium chloride interacts with water through ion-dipole interactions, while isopropyl alcohol forms hydrogen bonds with water.

Step-by-step explanation:

The solvents used in the experiment are 5% sodium chloride (aqueous) and 5% isopropyl alcohol (aqueous). Let's look at the molecular diagrams of how these substances interact in water:

Sodium Chloride (NaCl): Sodium chloride is an ionic compound, made up of sodium ions (Na+) and chloride ions (Cl-). In water, the positive end of the water molecule (the hydrogen atom) is attracted to the negative chloride ion, while the negative end of the water molecule (the oxygen atom) is attracted to the positive sodium ion. These attractions between the ions and the polar water molecules are known as ion-dipole interactions.

Isopropyl Alcohol (C3H8O): Isopropyl alcohol is a covalent compound. In water, the oxygen atom in the isopropyl alcohol molecules can form hydrogen bonds with the hydrogen atoms in the water molecules. These hydrogen bonds are the main intermolecular attraction between isopropyl alcohol and water.