Question

Suppose a piece of dust is stuck to a cd such that it does not slip even when the cd is spinning. show answer no attempt 50%.

if the constant spin rate of the cd is 420 rpm, then what angular distance, in radians, is traveled by the piece of dust in 2.5

Answer 1

To find the angular distance traveled by the piece of dust on the CD spinning at 420 rpm in 2.5 minutes, convert the rpm to rad/s and then multiply by the time in seconds, resulting in an angular distance of 6600 radians.

Step-by-step explanation:

To calculate the angular distance traveled by a piece of dust on a spinning CD at a constant rate of 420 revolutions per minute (rpm) in 2.5 minutes, we can follow these steps: First, we convert the spin rate from rpm to radians per second (rad/s) since the angular distance is generally measured in radians. One revolution is equal to 2π radians, and there are 60 seconds in one minute, so:

(420 rpm) × (2π rad/rev) × (1 min/60 s) = 44 rad/s

Now, we can find the angular distance by multiplying the angular velocity by the time in seconds:

(44 rad/s) × (2.5 min) × (60 s/min) = 6600 radians