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Which of the following instructions forces the rightmost bit of $s3 to be 1? (type the exact answer from among the two provided).

a. _____ $s3, $s3, 1
b. andi
c. ori
d. Ignore -- choose from the two possible answers provided
e. Ignore -- choose from the two possible answers provided

User Cjoerg
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1 Answer

3 votes

Final answer:

The 'ori' instruction is used to force the rightmost bit of register $s3 to be 1, by performing a bitwise OR operation with the immediate value of 1.

Step-by-step explanation:

The instruction that forces the rightmost bit of $s3 to be 1 is the 'ori' instruction. This stands for 'or immediate', which performs a bitwise OR operation between a register and an immediate value. If you want to set the rightmost bit to 1, you can OR the register's current value with 1. The instruction would look like ori $s3, $s3, 1.

The correct answer is b. andi. By using the bitwise AND operation, we can force the rightmost bit of $s3 to be 1. The AND operation compares each bit of the two operands and returns 1 only if both bits are 1. Since 1 AND 1 equals 1, performing $s3 AND 1 will set the rightmost bit of $s3 to be 1.

Therefore answer is c. ori.

User Dmitrybelyakov
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