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All P-Cl bond lengths are equal in PCl₃ but different in PCl₅.

Reason: Hybrid state of the central atom is different in different molecules.
(a) Both assertion and reason are true, and the reason is the correct explanation of the assertion.
(b) Both assertion and reason are true, but the reason is not the correct explanation of the assertion.
(c) Assertion is true, but the reason is false.
(d) Both assertion and reason are false.

User Adamski
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1 Answer

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Final answer:

The assertion that P-Cl bond lengths are equal in PCl₃ but different in PCl₅ is true due to their respective molecular geometries and hybridizations. PCl₃ has a trigonal pyramidal shape with sp³ hybridization, while PCl₅ has a trigonal bipyramidal shape with sp³d hybridization.

Step-by-step explanation:

The question addresses the bond lengths in two different phosphorus compounds: phosphorus trichloride (PCl₃) and phosphorus pentachloride (PCl₅). In PCl₃, all P-Cl bonds are equal in length, which can be attributed to the trigonal pyramidal molecular geometry and sp³ hybridization. This equality in bond length is due to the symmetric arrangement of the chlorine atoms around the central phosphorus atom. On the other hand, PCl₅ has different P-Cl bond lengths; this is due to the compound's trigonal bipyramidal geometry. There are axial and equatorial positions in this geometry with sp³d hybridization of the central P atom, leading to different bond lengths.

Moreover, the assertion and reason being analyzed are incomplete without context. However, the assertion that P-Cl bond lengths are equal in PCl₃ but different in PCl₅ is true. Yet, regarding PCl₃ and PCl₅ reacting with water to yield hydrogen chloride and an oxyacid, this is unrelated to the bond length issue.

User Jackuars
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