Final answer:
To find the height from which a parachutist bailed out, calculate the initial fall using gravity, then determine the height fallen during deceleration after the parachute opened, and add them together.
Step-by-step explanation:
Calculating the Height from Which a Parachutist Bailed Out
To determine the height from which a parachutist bailed out, we need to solve the problem in two parts: the free fall part and the deceleration part after opening the parachute. Initially, during the free fall, the parachutist falls 50 meters without friction, accelerating at 9.8 m/s² (the acceleration due to gravity).
The speed of the parachutist after the first 2 seconds can be calculated using the formula V = at, where 'a' is the acceleration and 't' is the time. Thus, V = 9.8 m/s² • 2 s = 19.6 m/s.
After the parachute opens, there's a deceleration of 2 m/s² until the parachutist reaches the ground with a speed of 3 m/s. We can use the final velocity formula, which is V² = U² + 2as, where 'V' is the final velocity, 'U' is the initial velocity, 'a' is the acceleration (or deceleration, in this case), and 's' is the displacement. Substituting the values, we get 3² = 19.6² - 2² • (9.8)•s. Solving for 's' gives the height of fall during deceleration.
Adding this height to the initial 50 meters of free fall will give us the total height from which the parachutist bailed out.