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A person pushed a 25-kg crate of pumpkins with 30 N of applied force. Friction resists the motion with 2.5 Newtons. What is the Normal Force on the crate?

User Arno
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Final answer:

The normal force on the crate is equal to its weight, which is calculated as the mass of the crate multiplied by the acceleration due to gravity, resulting in a normal force of 245 N.

Step-by-step explanation:

To calculate the normal force on the crate, we first need to recognize that the normal force is the force exerted by a surface to support the weight of an object resting on it, and it is perpendicular to the surface.

In this case, since the crate is on a horizontal surface and there are no vertical forces other than gravity and the normal force, the normal force must be equal to the weight of the crate.

The weight of the crate (W) can be calculated using the equation W = m × g, where m is the mass of the crate and g is the acceleration due to gravity (9.80 m/s²).

Thus, the weight of the 25-kg crate is W = (25 kg)(9.80 m/s²)

= 245 N.

Since there are no other vertical forces, the normal force (N) is equal to the weight of the crate: N = 245 N.

This means the surface is exerting a force of 245 N to support the crate, and by Newton's third law of motion, the crate exerts the same force back onto the surface.

User Andrew Sayer
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