Based on the available information, the probability of getting at least two heads when three unbiased coins are tossed simultaneously is 0.5 or 50%.
When three unbiased coins are tossed simultaneously, there are 2³ = 8 possible outcomes, which are:
HHH, HHT, HTH, THH, HTT, THT, TTH, TTT
where H represents a head and T represents a tail.
To find the probability of getting at least two heads, we need to count the number of outcomes that have two or three heads, and then divide by the total number of outcomes.
The outcomes that have two or three heads are:
HHH, HHT, HTH, THH
So, there are 4 outcomes that have at least two heads.
Therefore, the probability of getting at least two heads is:
P(at least two heads) = number of outcomes with at least two heads / total number of outcomes
= 4 / 8
= 1/2
= 0.5
So, the probability of getting at least two heads when three unbiased coins are tossed simultaneously is 0.5 or 50%.