691 views
5 votes
In a double slit experiment, the two slits are 1mm apart and the screen is placed 1m away. A monochromatic light of wavelength 500nm is used. What will be the width of each slit for obtaining ten maxima of double slit within the central maxima of single-slit pattern?

(a) 0.2mm
(b) 0.1mm
(c) 0.5mm
(d) 0.02mm

1 Answer

3 votes

The width of each slit should be 0.2 mm, option A.

How to find width?

This essentially means that the width of the central maximum in the single-slit pattern should be ten times the width of each double-slit fringe. Therefore:

Width of central maxima in a single slit diffraction = 2λD / a

Fringe width in double slit pattern:

β = λD / d

Applying the Values:

d = 1mm (slit separation which is 10⁻³ m)

λ = 500nm (500 × 10⁻⁹ m)

d = 10⁻³ m

D = 1 mm

Substituting the formulas for each width:

10 × β = 2λD / a

Simplifying:

10 × λD/d = 2λD / a

Solving for a:

a = d / 5 mm

a = 0.2 mm

Therefore: a = 0.2 mm

Conclusion:

For ten double-slit maxima to fit within the central maximum of the single-slit pattern, the width of each slit should be 0.2 mm. So, the correct answer is (a) 0.2 mm

User Richardaday
by
7.5k points