When it was subjected to some internal pressure, its nominal perimeter in the cylindrical portion increased by 0.1%, and the corresponding wall thickness became a) decreased by 0.1%
How to find rate?
Poisson's ratio (
) is defined as the ratio of transverse contraction strain to longitudinal extension strain in the direction of stretching force. Mathematically, it is expressed as:
![\[ \\u = -\frac{\varepsilon_{\text{transverse}}}{\varepsilon_{\text{longitudinal}}} \]](https://img.qammunity.org/2024/formulas/physics/high-school/to7jwbl26b9tdki5k8dwfo6jzzqyj9ctk1.png)
Where:
= transverse strain,
= longitudinal strain.
The relationship between the change in diameter (
), change in length (
), and Poisson's ratio is given by:
![\[ (\Delta D)/(D) = -\\u (\Delta L)/(L) \]](https://img.qammunity.org/2024/formulas/physics/high-school/ykbgslzz4crs66q5pf9vhwh083dvlki4ts.png)
Given that the nominal perimeter (P) is related to the diameter (D) by
, express the change in perimeter as:
![\[ (\Delta P)/(P) = (\Delta D)/(D) \]](https://img.qammunity.org/2024/formulas/physics/high-school/4kowba6bxnwvzvav0w667sbcvbm464lvsy.png)
Now, if the nominal perimeter increases by 0.1%, then
(0.1%).
Substitute this into the relationship and solve for
:
![\[ 0.001 = -\\u (\Delta L)/(L) \]](https://img.qammunity.org/2024/formulas/physics/high-school/mecwepl8r8qdi4lbjl8o9clzlibcppzn6b.png)
Given that
, substitute this value:
![\[ 0.001 = -(1)/(3) (\Delta L)/(L) \]](https://img.qammunity.org/2024/formulas/physics/high-school/62dctixsdok2jyobfic232qtaq9536d2tk.png)
Now, solve for
:
![\[ (\Delta L)/(L) = -3 * 0.001 \]](https://img.qammunity.org/2024/formulas/physics/high-school/e5k82u76ct6n5p02os5v5f2khsah2a1qpf.png)
![\[ (\Delta L)/(L) = -0.003 \]](https://img.qammunity.org/2024/formulas/physics/high-school/3r7tfop2ujuwachp2cftfpeuo3c3j7gkgs.png)
So, the longitudinal strain (
) is -0.003 or -0.3%.
Now, the wall thickness is related to the diameter by:
.
If
, then:
.
This means the wall thickness decreases by 0.3%.
Therefore, the correct answer is:
a) Decreased by 0.3%