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3 votes
The table below shows two equations:

Equation 1
Equation 2
14x-31-5-4
12x+31+8=3
Which statement is true about the solution to the two equations? (1 point)
O Equation 1 and equation 2 have no solutions.
O Equation 1 has no solution, and equation 2 has solutions x = -4, 1.
O The solutions to equation 1 are x = 3, -1.5, and equation 2 has no solution.
O The solutions to equation 1 are x = 3,-1.5, and equation 2 has solutions x = -4, 1.

User JPocoata
by
7.5k points

1 Answer

3 votes

Final answer:

Equation 1 has a solution of x = 23/19 and Equation 2 has a solution of x = -3.

Step-by-step explanation:

The given equations are:

Equation 1: 14x - 31 = -5x - 4

Equation 2: 12x + 31 + 8 = 3

To solve Equation 1, we can combine like terms:

19x - 27 = -4

Adding 27 to both sides:

19x = 23

Dividing both sides by 19:

x = 23/19

To solve Equation 2, we can combine like terms:

12x + 39 = 3

Subtracting 39 from both sides:

12x = -36

Dividing both sides by 12:

x = -3

Therefore, the solution to Equation 1 is x = 23/19 and the solution to Equation 2 is x = -3.

User Hyiltiz
by
8.1k points

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