Final answer:
The concentrations of H3O+ and OH− in pure water at 10 degrees Celsius, with a Kw of 0.293 x 10−14, are both 1.71 x 10−7 M, calculated by taking the square root of the Kw value.
Step-by-step explanation:
To determine the concentrations of H3O+ and OH− in pure water at 10 degrees Celsius with the water dissociation constant, Kw, being 0.293 x 10−14, we must recognize that pure water is neutral, meaning that the concentrations of H3O+ and OH− are equal. Therefore, to find each concentration, we take the square root of the Kw.
Using the provided Kw value at 10 degrees Celsius:
- Kw = [H3O+][OH−]
- Kw = 0.293 x 10−14
Since [H3O+] = [OH−], we can represent both concentrations with the variable x:
x = sqrt(Kw)
x = sqrt(0.293 x 10−14)
x = 1.71 x 10−7 M
Therefore, the concentration of H3O+ is 1.71 x 10−7 M and the concentration of OH− is also 1.71 x 10−7 M.