Final answer:
The force of gravity between the 6.5 kg and 7.9 kg bowling balls 0.84 m apart is calculated using the law of universal gravitation to be approximately 4.80 × 10-9 newtons.
Step-by-step explanation:
The question asks for the force of gravity exerted on two bowling balls by each other. According to Newton's law of universal gravitation, the force of gravity (F) between two objects can be calculated by the equation F = G*(m1*m2)/r2, where G is the gravitational constant (6.67430 × 10-11 N · (m/kg)2), m1 and m2 are the masses of the objects, and r is the distance between the centers of the two masses.
Given that we have a 6.5 kg bowling ball and a 7.9 kg bowling ball 0.84 m apart, we can substitute the values into the formula:
F = (6.67430 × 10-11 N · m2/kg2) * (6.5 kg * 7.9 kg) / (0.84 m)2
F = (6.67430 × 10-11) * (51.35 kg2) / (0.7056 m2)
F ≈ 4.80 × 10-9 N
Therefore, the force of gravity exerted on each of the bowling balls by the other is approximately 4.80 × 10-9 newtons.
To calculate the force of gravity exerted by one bowling ball on the other, we can use the formula for gravitational force:
F = G * ((m1 * m2) / r^2)
where F is the force of gravity, G is the gravitational constant (approximately 6.6743 x 10^-11 Nm^2/kg^2), m1 and m2 are the masses of the two bowling balls, and r is the distance between their centers. Plugging in the values, we have:
F = (6.6743 x 10^-11) * ((6.5 * 7.9) / (0.84^2))
F ≈ 4.895 x 10^-8 N
Therefore, the force of gravity exerted on each bowling ball by the other bowling ball is approximately 4.895 x 10^-8 Newtons.