Final answer:
The sum of two numbers is 33, and one number is 2 times the other. By using algebra, we determine the smaller number to be 11 and the larger to be 22.
Step-by-step explanation:
The problem here is a simple algebraic equation. We are given that the sum of two numbers is 33, and one number is 2 times larger than the other.
To find these numbers, we can let the smaller number be x and the larger number be 2x.
According to the problem, x + 2x = 33. When we combine like terms, we get 3x = 33.
Dividing both sides of the equation by 3 gives us x = 11, which is the smaller number.
To find the larger number, we multiply 11 by 2, giving us 22. Therefore, the two numbers are 11 and 22.