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H(t)=-16t^2+128t
after how many seconds will the rocket be 112 feet above the ground

User JoseJC
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1 Answer

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Final answer:

To find the time when the rocket is 112 feet above the ground, we solve the quadratic equation h(t) = -16t^2 + 128t by setting it equal to 112 and factoring. The rocket is at 112 feet at two times: 1 second (on the way up) and 7 seconds (on the way down).

Step-by-step explanation:

To determine after how many seconds the rocket will be 112 feet above the ground, we need to solve the equation given by the rocket's height as a function of time, h(t) = -16t^2 + 128t. We want to find the time t when the height is 112 feet. Therefore, we set the equation equal to 112 and solve for t.

112 = -16t^2 + 128t

This is a quadratic equation that can be rewritten as:

0 = -16t^2 + 128t - 112

Dividing the entire equation by -16 to simplify gives:

0 = t^2 - 8t + 7

Factoring this equation, we get:

0 = (t - 7)(t - 1)

So, the possible values for t are t = 7 seconds and t = 1 second. Both values are the times when the rocket is at a height of 112 feet, once on the way up and once on the way down.

User Chen Dachao
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