Final answer:
To produce a 100 mL solution of 1.68 x 10⁻³ M MnO4^-, 70 mL of a 2.40 x 10⁻³ M KMnO4 solution is required.
Step-by-step explanation:
To calculate the volume of a solution that is required to produce another solution with a given concentration, we can use the molarity equation:
M1 * V1 = M2 * V2
In this case, we're given:
- M1 = 2.40 x 10⁻³ M
- V1 = unknown
- M2 = 1.68 x 10⁻³ M
- V2 = 100 mL
Plugging these values into the equation, we have:
(2.40 x 10⁻³ M) * V1 = (1.68 x 10⁻³ M) * 100 mL
Solving for V1:
V1 = (1.68 x 10⁻³ M) * 100 mL / (2.40 x 10⁻³ M)
V1 = 70 mL
Therefore, 70 mL of the 2.40 x 10⁻³ M KMnO4 solution is required to produce 100 mL of a standard 1.68 x 10⁻³ M MnO4- solution.