Question

A car travelling at 5.0 m/s starts to speed up. After 3.0 s its velocity has increased to 11 m/s. a) What is its acceleration? (Assume it to be uniform.) b) What distance does it travel while speeding up?​

Answer 1

initially, the car is traveling at 5.0 m/s.

so, we know acceleration for changing velocity is :

a = (v-v
`_(o)`)/t ..........(i)

where v is the final velocity

v
`_(o)` is the initial velocity

t is the time taken to change velocity

Now, as per the question :

initial velocity, v
`_(o)`=5.0 m/s

final velocity, v =11 m/s

time taken, t = 3 s

putting the values in equation (i),

a = ( 11-5 )/3

a = 2 m/s²

Therefore, a, after 3 s, is 2 m/s².