Question

I need help with this.

Answer 1

Explanation:

ax² + bx + c = 0

D = b² - 4ac

If D > 0 , then quadratic equation has 2 roots.

If D = 0 , then quadratic equation has 1 roots.

If D > 0 , then quadratic equation has No roots in the set of real numbers.

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2y² + 4y = 3

2y² + 4y - 3 = 0

a = 2 , b = 4 , c = - 3

D = 4² - 4(2)( - 3) = 40 > 0 ( 2 solutions )

`y_(12)` = ( - 4 ± 2√10 ) ÷ 4

`y_(1)` =
`(-2+√(10) )/(2)`

`y_(2)` =
`(-2-√(10) )/(2)`