Question

What is the output of the following loop?

count = 5;
cout << 'St';
do
{
cout << 'o';count--;
}
while (count <= 5);

Answer 1

The output of the loop would be "Stoooooo" as the do-while loop will execute at least once and then continue to run until the count is less than 0.

Step-by-step explanation:

The student asked what the output of the following loop would be:

count = 5; cout << 'St'; do{ cout << 'o'; count--; }while (count <= 5);

Since the loop is a do-while loop, it guarantees that the body of the loop will be executed at least once. After printing 'St', the loop will then print 'o' and decrement the count by 1. Since count is initially 5, after the first iteration, it becomes 4. However, because the condition of the loop checks if count is less than or equal to 5, the loop will only terminate when count goes below 0. This will result in 'o' being printed a total of 6 times, leading to the final output being "Stoooooo".