Question

1248g of barium chloride reacts with 684g of aluminum sulfate, forming 1398g of barium sulfate and 534g of aluminum chloride. Balance the equation:

BaCl_2 + Al_2(SO_4)_3 -> BaSO_4 + AlCl_3
A) 3BaCl_2 + 2Al_2(SO_4)_3 -> 3BaSO_4 + 2AlCl_3
B) BaCl_2 + Al2(SO_4)_3 -> BaSO_4 + 2AlCl_3
C) 2BaCl_2 + Al_2(SO_4)_3 -> 2BaSO_4 + AlCl_3
D) 4BaCl_2 + 3Al2(SO_4)_3 -> 4BaSO_4 + 3AlCl_3

Answer 1

The correctly balanced equation for the reaction between barium chloride and aluminum sulfate is 3BaCl2 + 2Al2(SO4)3 -> 3BaSO4 + 2AlCl3, which corresponds to option A.

Step-by-step explanation:

The goal is to balance the chemical equation for the reaction between barium chloride (BaCl2) and aluminum sulfate (Al2(SO4)3) forming barium sulfate (BaSO4) and aluminum chloride (AlCl3). By applying the law of conservation of mass, we can balance the equation by ensuring that the number of atoms for each element on the reactant side is equal to the number on the product side.

Here's the balanced chemical equation:
3BaCl2 + Al2(SO4)3 -> 3BaSO4 + 2AlCl3

The correct balanced equation corresponds to option A: 3BaCl2 + 2Al2(SO4)3 -> 3BaSO4 + 2AlCl3.