Question

83.0 g Lithium Cyanide (LiCN)
calculate this to molar mass and moles. Please

Answer 1

Molar mass:-

`\\ \sf\longmapsto LiCN`

`\\ \sf\longmapsto 7u+12u+14u`

`\\ \sf\longmapsto 21u+12u`

`\\ \sf\longmapsto 33u`

`\\ \sf\longmapsto 33g/mol`

• Given mass=83g

No of moles=Given Mass/Molar mass

`\\ \sf\longmapsto (83)/(33)`

`\\ \sf\longmapsto 2.5mol`

Answer 2

32.958 g/mol

2.52 moles

Step-by-step explanation:

Finding the molar mass:

Use the periodic table to determine the masses of each element

6.94+12.011+14.007=32.958 g/mol

Moles:

83 g*1 mol/32.958 g = 2.5183566964 moles