Question

What is the number of atoms present in 3.55 moles of bromine (Br)? Choose the most accurate value from the following options:

A) 3.55×6.02×10²³ atoms
B) 3.55×10²³ atoms
C) 6.02×10²³ atoms
D) 1.8061×10²⁴ atoms

Answer 1

The number of atoms present in 3.55 moles of bromine (Br) is 1.8061 × 10²⁴ atoms, which corresponds to option D.

Step-by-step explanation:

To find the number of atoms present in 3.55 moles of bromine (Br), we utilize Avogadro's number, which is 6.022 × 10²³ atoms per mole. Since bromine exists as diatomic molecules Br₂, each mole of Br₂ consists of 2 atoms of bromine.

Therefore, we calculate the number of atoms as follows: 3.55 moles × 2 atoms/mole × 6.022 × 10²³ atoms/mole = 1.8061 × 10²⁴ atoms of bromine.

Thus, the most accurate value from the given options is D) 1.8061 × 10²⁴ atoms.