Final answer:
Based on the given IR spectrum showing a strong peak at 1716 cm⁻¹ in the carbonyl region and a broad signal suggesting an O-H stretch, the compound is classified as a carboxylic acid. The correct answer is D.
Step-by-step explanation:
To examine the IR spectrum and classify the compound based on the absorption peaks, we look for characteristic absorptions that identify certain functional groups. Since the spectrometer is detecting a strong peak in the carbonyl region, specifically at 1716 cm⁻¹, this indicates the presence of a carbonyl group. This absorption falls within the range where carboxylic acids, esters, aldehydes, and ketones typically absorb (1700-1750 cm⁻¹).
A low, broad absorbance band, typical for an alcohol, is also noted; however, its slight displacement to the longer wavelength signifies that this could be the characteristic carboxylic acid O-H bond stretching absorbance, which is typically found in the region overlapping with the C-H stretch. Considering the strong absorbance at 1716 cm⁻¹, and the broad signal that could indicate the O-H stretching of a carboxylic acid, the compound can be classified as a carboxylic acid.