Question

PLEASE HELP ME

Write the equation of a line in slope intercept form that is perpendicular to Y= -1/3x+4 and pass through the point (-2,-5)

Answer 1

y = 3x + 1

Explanation:

The general form of the slope intercept form is y = mx + b where m is the slope and b is the y-intercept.

In perpendicular lines, we find the slope of the second equation (m2) using the formula:

`m_(2)=-(1)/(m_(1) )`

Since -1/3 is m1 we have:

`m_(2)=-(1)/(-((1)/(3)) ) \\ m_(2)=3`

Now that we've found the slope of the second line, we simply need to find b or its y-intercept by plugging in (-2, -5) and our slope:

`-5=3(-2)+b\\-5=-6+b\\1=b`

Thus, the equation of the second line is y = 3x + 1