If 45.0 mL of a 6.0 M HCI solution are dilute with pure water to a volume of 1.0 L , what is the concentration of the resulting solution?

Marlan asked Jan 21, 2023

44,139 views

43 votes

Marlan asked Jan 21, 2023

3.1k points

Your comment on this question:

Email me at this address if a comment is added after mine:Email me if a comment is added after mine

Privacy: Your email address will only be used for sending these notifications.

Email me at this address if my answer is selected or commented on:Email me if my answer is selected or commented on

Privacy: Your email address will only be used for sending these notifications.

11 votes

Answer: 0.27 M

Step-by-step explanation:

c1V1=c2V2

c1=6.0 M;V1=45.0 mL

c2=?;V2=1.0 L=1000 mL

c2=(c1V1)/V2

c2=((6.0)(45.0))/1000

c2=0.27 M

Tanu Garg answered Jan 25, 2023

3.4k points

Email me at this address if a comment is added after mine:Email me if a comment is added after mine

Privacy: Your email address will only be used for sending these notifications.

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

1.6m questions

2.0m answers